The villainous Dr. Schrödinger has developed a growth ray and intends to create an army of giant cats to terrorize the city. Your team of secret agents has tracked him to his underground lab. You burst in to find… that it’s a trap!
邪惡的薛丁格博士 發明一種成長射線, 打算要創造出一支巨貓軍團, 讓城市陷入恐怖。 你的秘密幹員團隊 追蹤他到他的地下實驗室。 你闖進去之後 卻發現……這是陷阱!
Dr. Schrödinger has slipped into the next room to activate his device and disabled the control panel on the way out.
薛丁格博士已經溜到 隔壁房間啟動他的裝置, 並在離開的時候讓控制面版失效。
Fortunately, your teammates are masters of spy-craft. Agent Delta has hacked into the control panel and managed to reactivate some of its functionality. Meanwhile, Agent Epsilon has searched through surveillance to find the code for the door: 2, 10, 14.
幸運的是,你的隊員 是間諜技藝高手, 德耳塔幹員駭入了控制面板, 成功將某些功能重新啟動恢復。 同時,伊普西龍幹員 透過監視系統搜尋, 找到了開門的密碼: 2、 10、 14。
All you have to do is enter those numbers and you’ll be free. But there’s a problem. The control panel has only three buttons: one which adds 5 to the display number, one which adds 7, and one which takes the square root. You need to make the display output the numbers 2, 10, and 14, in that order. It’s okay if it outputs different numbers in between, but there’s no way to reset the display, so once you get to 2, you’ll have to continue on to 10 and 14 from there.
你只需輸入那些數字就自由了。 但有一個問題。 控制面版只有三個按鈕: 一個按鈕會將顯示號碼加上 5, 一個按鈕會加上 7, 還有一個會取平方根。 你得要讓輸出的顯示數字 是 2、10、14,且順序不能錯。 如果在中間輸出了 不同的數字也沒關係, 但顯示是無法重設的, 所以一旦你顯示出了 2, 你就得要接著弄出 10 和 14。
Not only that, Agent Delta explains that there are other traps built into the panel. If it ever shows the same number more than once, a number greater than 60, or a non-whole number, the room will explode.
不僅如此,德耳塔幹員解釋說, 那面版還有內建其他陷阱。 如果同一個數字出現超過一次, 或有一個數字超過 60, 或有非整數出現, 房間就會爆炸。
Right now, the display reads zero, and time is running out. There’s only one way to solve the puzzle, with a few small variations. How will you input the code to escape from Dr. Schrödinger’s lair and save the day? Pause the video now if you want to figure it out for yourself!
現在,顯示的數字是 0, 且時間快要用盡了。 只有一種方式可以解開這道謎, 要用到幾個小小的變化。 你要如何輸入密碼, 以逃離薛丁格博士的藏身處, 拯救世界? 如果你想要自己解解看, 在這裡暫停!
Answer in: 3
答案即將公佈:3,
2
2,
1.
1。
You look over your options. Adding 5 or 7 increases the number, and the square root button will make it smaller. But there are only a few options where you can use that button: 4 9 16 25, 36, and 49. You’d love to make 4 or 16. Then you could hit the square root button once or twice to get 2. But you can’t make either with just the 5 and 7 buttons. What will you do?
你看著你的選擇。 加上 5 或 7 會讓數字變大, 平方根按鈕會讓數字變小。 但只有少數情況下 可以按平方根按鈕: 4、 9、 16、 25、 36, 及 49。 你很想要得到 4 或 16。 這樣你就可以按平方根按鈕 一次或兩次來得到 2。 但是用按鈕 5 或 7 是辦不到的。 你會怎麼做?
You look at the other possible options for numbers you could take the square root of. Nine you can’t reach. Twenty-five and 49 would take you back to 5 or 7, and you can already get to each of those. Thirty-six is your only option.
你會考慮用其他 可以取平方根的數字。 你不能做出 9。 若做出 25 或 49, 只會讓你回到 5 或 7, 你本來就可以做到 5 和 7 了。 所以 36 是你唯一的選擇。
You add 5, 7, 5, 7, 5, 7, and then hit the square root button. Why that series of 5s and 7s? It’s somewhat arbitrary, but you know that you want to avoid 10, 14, and perfect squares, since you’ll need them later. This gets you to 6. Does that help? Looking at your options, you see that 16 is now in your sights. You add 5 twice more to reach it. Then hit square root twice. That gets you to 2. You’re on your way!
你把 5、 7、 5、 7、 5、 7 相加, 接著按下平方根按鈕。 為什麼加 5 和 7 的順序要這樣? 的確加法的順序可以隨意, 但你知道你會希望避免 10、14, 以及可取平方根的數字, 這些要留著之後使用。 這樣就讓你得到了 6。 那有幫助嗎? 你看著你的選項, 發現可以做出 16。 你加了 5 兩次,得到 16。 接著按了兩次平方根按鈕。 你就得到了 2。 你有進展了!
Now to 10. You can’t get straight there through addition alone, so you’re going to have to reach another square. Taking the square root of 9 or 25 would get you to a good place, but it turns out that 25 is unreachable from 2. So you add 7 to get to 9, then take the square root again. That gets you to 3. Adding 7 again makes 10.
現在需要 10。 你無法直接用加法得到它, 所以你又得要用另一個平方根。 若能取得 9 或 25 的 平方根,你就很有優勢, 但從 2 是無法得到 25 的。 所以你加上 7,得到了 9, 接著再取平方根。 你就得到了 3。 加上 7 之後產出了 10。
Finally, you need to reach 14. Thinking backwards, you imagine where you could be before 14: 7 or 9. But 9 won’t work because you’ve already used 9. However, you could get to 7 by reaching 49 first. You add your way towards it, being careful not to hit any of the numbers you’ve hit so far. You thread your way carefully, adding five 5s and two 7s. Then, square root to 7, and add 7 more. The door opens, and you’re out of the trap.
最後,你需要做出 14。 反向思考,你先去想 在 14 之前要得到什麼數字: 7 或 9。 但 9 已經被用過了。 然而,你可以 先得到 49 再得到 7。 你用加法向上加到 49, 要很小心過程不要做出 你已經用過的數字。 你很小心地設計加法, 加上 5 個 5 和 2 個 7。 接著,取平方根 得到 7,再加上 7。 門打開了,你脫離了陷阱。
Thanks to your problem-solving skills, your team gets Schrödinger’s cats out of the box in the nick of time. As for Schrödinger, you can be certain of one thing: he’ll be spending quite some time in a box of his own.
幸虧有解決問題的技巧, 你的團隊及時將薛丁格的貓 從盒子裡救出來。 至於薛丁格,你能確定一件事: 他會花許多時間 待在他自己的盒子當中。